Basics of Computer Architecture MCQs and Notes

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Mr. Dubey • 51.67K Points
Coach

Q 11. The master indicates that the address is loaded onto the BUS, by activating signal.

(A) MSYN
(B) SSYN
(C) WMFC
(D) INTR

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Mr. Dubey • 51.67K Points
Coach

Q 12. Which of the architecture is power efficient?

(A) CISC
(B) RISC
(C) ISA
(D) IANA

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Mr. Dubey • 51.67K Points
Coach

Q 13. The Sun micro systems processors usually follow            architecture.

(A) CISC
(B) ISA
(C) ULTRA SPARC
(D) RISC

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Mr. Dubey • 51.67K Points
Coach

Q 14. If a processor does not have any stack pointer register, then

(A) It cannot have subroutine call instruction
(B) It can have subroutine call instruction, but no nested subroutine
(C) Nested subroutine calls are possible, but interrupts are not
(D) All sequences of subroutine calls and also interrupts are

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Mr. Dubey • 51.67K Points
Coach

Q 15. Which of the following register is used in the control unit of the CPU to indicate the next instruction which is to be executed ?

(A) Accumulator
(B) Index register
(C) Instruction decoder
(D) Program counter

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Mr. Dubey • 51.67K Points
Coach

Q 16. The addressing mode, where you directly specify the operand value is                

(A) Immediate
(B) Direct
(C) Definite
(D) Relative

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Mr. Dubey • 51.67K Points
Coach

Q 17. The effective address of the following instruction is MUL 5(R1,R2).

(A) 5+R1+R2
(B) 5+(R1*R2)
(C) 5+[R1]+[R2]
(D) 5*([R1]+[R2])

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Mr. Dubey • 51.67K Points
Coach

Q 18.            addressing mode is most suitable to change the normal sequence of execution of instructions.

(A) Relative
(B) Indirect
(C) Index with Offset
(D) Immediate

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Mr. Dubey • 51.67K Points
Coach

Q 19. The addressing mode which makes use of in-direction pointers is              

(A) Indirect addressing mode
(B) Index addressing mode
(C) Relative addressing mode
(D) Offset addressing mode

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Mr. Dubey • 51.67K Points
Coach

Q 20. In the following indexed addressing mode instruction, MOV 5(R1), LOC the effective address is              

(A) EA = 5+R1
(B) EA = R1
(C) EA = [R1]
(D) EA = 5+[R1]

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