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Math MCQ Questions with answers

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Learn Math MCQs [Page 1 of Department 7]

1) A train 175 m long running with a speed of 63 km/hr will pass a man in

(A) 8 sec
(B) 12 sec
(C) 10 sec
(D) 6 sec
Correct Answer - Option (C)

No Explanation found. Add Explanation and get +2 points.

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2) Average of 80 numbers are 42. When 5 more numbers are included, the average of 85 numbers become 45. Find the average of 5 numbers. 

(A) 82
(B) 89
(C) 93
(D) 98
Correct Answer - Option (C)

No Explanation found. Add Explanation and get +2 points.

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3) Find the average increase rate, if increase in the population in the first year is 30% and that in the second year is 40%.

(A) 41%
(B) 56%
(C) 40%
(D) 38%
Correct Answer - Option (A)

Explanation:
Let 100 be the original population. 1st year's population increased = 30% So, Population after first year = (100 + 30% of 100) = 130 Population in second year increases by 40%, Then Population = (130 + 40% of 130) = 182 The final population become 182 which was originally at 100. It means there is 82% increment in the population in 2 years So, Average increment = 822 = 41% Mind Calculation Method: Increase in population is given by, 100 == 30% ↑ ⇒ 130 == 40% ↑ ⇒ 182 Hence, average increase = 82/2 = 41%

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4) A batsman makes a score of 270 runs in the 87th inning and thus increase his average by a certain number of runs that is a whole number. Find the possible values of the new average. 

(A) 98
(B) 184
(C) 12
(D) All of these
Correct Answer - Option (D)

Explanation:
Part of the runs scored in the 87th innings will go towards increasing the average of the first 86 innings to the new average and remaining part of the runs will go towards maintaining the new average for the 87th innings. The only constraint in this problem is that there is increase in average by a whole number of runs. This is possible for all three options.

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5) The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 

(A) 123
(B) 127
(C) 235
(D) 305
Correct Answer - Option (B)

Explanation:
Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 = 127

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6) Which of the following has the most number of divisors?

(A) 99
(B) 101
(C) 176
(D) 182
Correct Answer - Option (C)

Explanation:
99 = 1 × 3 × 3 × 11 101 = 1 × 101 176 = 1 × 2 × 2 × 2 × 2 × 11 182 = 1 × 2 × 7 × 13 So, divisors of 99 are 1, 3, 9, 11, 33, 99 Divisors of 101 are 1 and 101 Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176 Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182 Hence, 176 has the most number of divisors.

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7) The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 

(A) 28
(B) 32
(C) 40
(D) 64
Correct Answer - Option (C)

Explanation:
Let the numbers be 2x and 3x Then, their L.C.M. = 6x So, 6x = 48 or x = 8 ∴ The numbers are 16 and 24 Hence, required sum = (16 + 24) = 40

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8) If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 

(A) 55/601
(B) 601/55
(C) 11/120
(D) 120/11
Correct Answer - Option (C)

No Explanation found. Add Explanation and get +2 points.

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9) The HCF and LCM of two numbers are 8 and 48 respectively. If one of the number is 24, then the other number is = ?

(A) 48
(B) 36
(C) 24
(D) 16
Correct Answer - Option (D)

Explanation:
HCF = 8 LCM = 48 One number = 24 Let other number be = y ∴ 24y = 48 × 8 ⇔ y = 16

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10) The least number which when divided by 4, 6, 8, 12 and 16 leaves remainder of 2 in each case is = ?

(A) 46
(B) 48
(C) 50
(D) 56
Correct Answer - Option (C)

Explanation:
LCM of (4, 6, 8, 12, 16) ⇒ 16 × 3 = 48 ∴ The number when divided by (4, 6, 8, 12, 16) leaves remainder 2 is = 48 + 2 = 50

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