Question

What does the & operator do when used with a proc in Ruby?

Accepted Answer

Converts the proc into a block so it can be passed to a method that expects a block parameter

Answer

Invokes the proc with the given arguments

Answer

Converts the proc into a lambda so it can be passed to a method that expects a lambda parameter

Answer

Converts the proc into a method so it can be called directly

Q. What does the & operator do when used with a proc in Ruby?

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