β
Correct Answer: (B)
file object = open(file_name [, access_mode][, buffering])
Explanation: open() function correct syntax with the parameter details as shown below: file object = open(file_name [, access_mode] [, buffering])
Explanation by: Mr. Dubey
open() function correct syntax with the parameter details as shown below: file object = open(file_name [, access_mode] [, buffering])
Discussion
Question Analytics
265
Total Visits
3 y ago
Published
Mr. Dubey
Publisher
84%
Success Rate