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M

Mr. Dubey • 100.64K Points
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Q. If the moment of inertia of a section about its axis is and its effective sectional area is, its radius of gyration r about the axis, is

  • (A) r = I/A
  • (B) r I/A)
  • (C) r = (I/A)
  • (D) r A/I)
  • Correct Answer - Option(B)
  • Views: 468
  • Filed under category Design of Steel Structures
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