πŸ“Š Ruby
Q. What is the output of the given code?
for counter in 1..5
case counter
when 0 .. 2
puts counter
puts "baby"
when 3 .. 6
puts counter
puts "little child"
when 7 .. 12
puts counter
puts "child"
else
puts counter
puts "adult"
end
end
  • (A) adult 1..5
  • (B) b alphabet b
  • (C) 1 baby 2 baby 3 little child 4 little child 5 little child
  • (D) adult
πŸ’¬ Discuss
βœ… Correct Answer: (C) 1 baby 2 baby 3 little child 4 little child 5 little child

You must be Logged in to update hint/solution

πŸ’¬ Discussion


πŸ“Š Question Analytics

πŸ‘οΈ
109
Total Visits
πŸ“½οΈ
2 y ago
Published
πŸŽ–οΈ
Mr. Dubey
Publisher
πŸ“ˆ
98%
Success Rate