Q. A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
β
Correct Answer: (B)
16
Explanation: Suppose boy got x sums right and 2x sums wrong,
then,
x+2x = 48
=> 3x = 48
=> x = 16
Explanation by: Mr. Dubey
Suppose boy got x sums right and 2x sums wrong,
then,
x+2x = 48
=> 3x = 48
=> x = 16
then,
x+2x = 48
=> 3x = 48
=> x = 16