Q. Find the odd number in the series:
7, 23, 58, 127, 269, 555
7, 23, 58, 127, 269, 555
✅ Correct Answer: (B)
261
Explanation: The order of above series is given as
First term = 7
Second term = ( First term x 2 ) +9
⇒ Second term = ( 7 x 2 ) + 9 = 14 + 9 = 23
Third term = ( Second term x 2 ) +11
⇒ Third term = ( 23 x 2 ) + 11 = 46 + 11 = 58 is wrong , 57 should be Third term because ( 23 × 2 ) + 11 = 57 .
Similarly we can find all others terms also.
Fourth term = ( Third term x 2 ) +13
⇒ Fourth term = ( 57 x 2 ) +13
Fifth term = ( Fourth term x 2 ) +15
⇒ Fifth term = ( 127 × 2 ) + 15 = 269
Sixth term = ( Fifth term x 2 ) +17
⇒ Sixth term = ( 269 × 2 ) + 17 = 555
Explanation by: Santosh Mishra
The order of above series is given as
First term = 7
Second term = ( First term x 2 ) +9
⇒ Second term = ( 7 x 2 ) + 9 = 14 + 9 = 23
Third term = ( Second term x 2 ) +11
⇒ Third term = ( 23 x 2 ) + 11 = 46 + 11 = 58 is wrong , 57 should be Third term because ( 23 × 2 ) + 11 = 57 .
Similarly we can find all others terms also.
Fourth term = ( Third term x 2 ) +13
⇒ Fourth term = ( 57 x 2 ) +13
Fifth term = ( Fourth term x 2 ) +15
⇒ Fifth term = ( 127 × 2 ) + 15 = 269
Sixth term = ( Fifth term x 2 ) +17
⇒ Sixth term = ( 269 × 2 ) + 17 = 555
First term = 7
Second term = ( First term x 2 ) +9
⇒ Second term = ( 7 x 2 ) + 9 = 14 + 9 = 23
Third term = ( Second term x 2 ) +11
⇒ Third term = ( 23 x 2 ) + 11 = 46 + 11 = 58 is wrong , 57 should be Third term because ( 23 × 2 ) + 11 = 57 .
Similarly we can find all others terms also.
Fourth term = ( Third term x 2 ) +13
⇒ Fourth term = ( 57 x 2 ) +13
Fifth term = ( Fourth term x 2 ) +15
⇒ Fifth term = ( 127 × 2 ) + 15 = 269
Sixth term = ( Fifth term x 2 ) +17
⇒ Sixth term = ( 269 × 2 ) + 17 = 555