Q. A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________
✅ Correct Answer: (A)
50 J
Explanation: Work done = 1/2*m*V2
Explanation by: Team MCQ Buddy
Work done = 1/2*m*V2