Q. Which hybridization is present on the carbon atoms of ethene (C2H4)?
✅ Correct Answer: (C)
sp2
Explanation: In ethene each carbon forms three sigma bonds (two C-H and one C-C) and one pi bond (C=C), which corresponds to sp2 hybridization (three hybrid orbitals and one unhybridized p orbital for the pi bond). sp3 implies four sigma bonds (single bonds only) — incorrect. sp corresponds to linear geometry with two pi bonds (as in acetylene) — incorrect. dsp2 is used in some transition-metal complexes, not in simple organic carbon atoms.
Explanation by: Sikhar Chaudhary
In ethene each carbon forms three sigma bonds (two C-H and one C-C) and one pi bond (C=C), which corresponds to sp2 hybridization (three hybrid orbitals and one unhybridized p orbital for the pi bond). sp3 implies four sigma bonds (single bonds only) — incorrect. sp corresponds to linear geometry with two pi bonds (as in acetylene) — incorrect. dsp2 is used in some transition-metal complexes, not in simple organic carbon atoms.