Q. A projectile is thrown at an angle of 45°. The ratio of its maximum height to horizontal range is:
✅ Correct Answer: (B)
1 : 4
Explanation: For θ = 45°, H = u²/4g and R = u²/g. Therefore, H:R = 1:4.
Explanation by: Tina Singh
For θ = 45°, H = u²/4g and R = u²/g. Therefore, H:R = 1:4.