Q. For the reaction N2 + 3H2 → 2NH3 if \(\frac{\Delta\left[\mathrm{NH}_{3}\right]}{\Delta t}\) = 2 × 10-4 mol L-1s-1, the value of \(\frac{-\Delta\left[\mathrm{H}_{2}\right]}{\Delta t}\) would be
  • (A) 1 × 10-4 mol L-1s-1
  • (B) 3 × 10-4 mol L-1s-1
  • (C) 4 × 10-4 mol L-1s-1
  • (D) 6 × 10-4 mol L-1s-1
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✅ Correct Answer: (B) 3 × 10-4 mol L-1s-1

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