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Correct Answer: (B)
n/2
Explanation: we can prove this by calculus. let x be the total number of vertices on set x. therefore set y will have n-x. we have to maximize x*(n-x). this is true when x=n/2.
Explanation by: Mr. Dubey
we can prove this by calculus. let x be the total number of vertices on set x. therefore set y will have n-x. we have to maximize x*(n-x). this is true when x=n/2.
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