Q. How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?

  • (A) 12
  • (B) 14
  • (C) 16
  • (D) 18
πŸ’¬ Discuss
βœ… Correct Answer: (B) 14
Explanation: total number of decimals to be represented = 10000 = 104 = 2n (where n is the number of bits required) = 213.29. therefore, the number of bits required for straight binary encoding = 14.

Published by Mr. Dubey ⭐ 111.54K Points at 17-Sep-2023 07:04 am in Digital Principles and System Design

Explanation by: Mr. Dubey
total number of decimals to be represented = 10000 = 104 = 2n (where n is the number of bits required) = 213.29. therefore, the number of bits required for straight binary encoding = 14.

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