M

Mr. Dubey • 52.26K Points
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Q. How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?

(A) 12
(B) 14
(C) 16
(D) 18
Correct : Option (B)

Explanation: 
 total number of decimals to be represented = 10000 = 104 = 2n (where n is the number of bits required) = 213.29. therefore, the number of bits required for straight binary encoding = 14.

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