Q. The following grammar G = (N, T, P, S)**spaceN = {S, A, B, C, D, E}**spaceT = {a, b, c}**spaceP : S → aAB**spaceAB → CD**spaceCD → CE**spaceC → aC**spaceC → b**spacebE → bc is

• (A) is type 3
• (B) is type 2 but not type 3
• (C) is type 1 but not type 2
• (D) is type 0 but not type 1