Q. If the total efficiency is 0.35 in arc welding. Then what is the welding speed in mm/sec if the cross-sectional area is 5mm2, welding power is 2 kW and the heat required in melting the metal is 100 J/mm3.
✅ Correct Answer: (A)
1.4
Explanation: n = (p×total efficiency)/(q×a), where p represents power, q represents heat transfer, and a represents the cross-sectional area.