The value of NA/(NA + NB), for steady state equimolal counter diffusion of two gases 'A' and 'B' is

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Q. The value of NA/(NA + NB), for steady state equimolal counter diffusion of two gases 'A' and 'B' is

(A) 1
(B) ∞
(C) 0.5
(D) 2

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✅ Correct Answer: (B) ∞

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