M Mr. Dubey • 100.64K Points Coach Q. What happens to Vmax and Km in case of uncompetitive inhibition when I = Ki'? (A) Lowers to 0.5 Vmax and 0.5 Km (B) Vmax is unchanged and Km increases 2Km (C) Lowers to 0.5 Vmax and Km remains unchanged (D) Lowers to 0.67 Vmax and Km increases to 2Km Correct Answer - Option(A) Views: 609 Filed under category Enzyme Engineering in Biotechnology Share
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