What happens to Vmax and Km in case of uncompetitive inhibition when I = Ki'?

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📊 Enzyme Engineering in Biotechnology

Q. What happens to Vmax and Km in case of uncompetitive inhibition when I = Ki'?

(A) Lowers to 0.5 Vmax and 0.5 Km
(B) Vmax is unchanged and Km increases 2Km
(C) Lowers to 0.5 Vmax and Km remains unchanged
(D) Lowers to 0.67 Vmax and Km increases to 2Km

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✅ Correct Answer: (A) Lowers to 0.5 Vmax and 0.5 Km

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