Q. For a Wilkinson power divider of insertion loss L and the coupler is matched to the external circuitry, and then the gain of the coupler in terms of insertion loss is:
β
Correct Answer: (B)
1/2l
Explanation: to evaluate the noise figure of the coupler, third port is terminated with known impedance. then the coupler becomes a two port device. since the coupler is matched, Πs=0 and Πout=s22=0. so the available gain is βs21β2. this is equal to 1/2l from the available data.