πŸ“Š Power Electronics
Q. In a push - pull converter, the filter capacitor can be obtained as
  • (A) Cmin = V / ( Vr L f2 )
  • (B) Cmin= ( 1 – D ) V / ( Vr L f2 )
  • (C) Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )
  • (D) Cmin= ( 1 – 2 D ) V / 42 ( Vr L f2 )
πŸ’¬ Discuss
βœ… Correct Answer: (C) Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )

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