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Mr. Dubey • 51.47K Points
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Q.) In a push - pull converter, the filter capacitor can be obtained as

(A) Cmin = V / ( Vr L f2 )
(B) Cmin= ( 1 – D ) V / ( Vr L f2 )
(C) Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )
(D) Cmin= ( 1 – 2 D ) V / 42 ( Vr L f2 )
Correct answer : Option (C) - Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )

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