Q. In a push - pull converter, the filter capacitor can be obtained as

(A) Cmin = V / ( Vr L f2 )
(B) Cmin= ( 1 – D ) V / ( Vr L f2 )
(C) Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )
(D) Cmin= ( 1 – 2 D ) V / 42 ( Vr L f2 )

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✅ Correct Answer: (C) Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )

Published by Mr. Dubey ⭐ 111.54K Points at 15-Sep-2023 12:50 am in Power Electronics

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