Q. In a locomotive, the ratio of the connecting rod length to the crank radius is kept very large in order to
✅ Correct Answer: (B)
minimize the effect of secondary forces
Dynamics of Machinery MCQs | Page - 4
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Q. Secondary forces in reciprocating mass on engine frame are
✅ Correct Answer: (B)
twice the frequency as of primary forces
Q. For a V-twin engine, which of the following means can be used to balance the primary forces?
✅ Correct Answer: (A)
Revolving balance mass
Q. The primary unbalanced force is maximum when the angle of inclination of the crank with the line of stroke is
✅ Correct Answer: (C)
180°
Q. From the following data of a 60 degree V-twin engine, determine the minimum value for primary forces in newtons:Reciprocating mass per cylinder = 1.5 Kg Stroke length = 10 cm Length of connecting rod = 25 cm Engine speed = 2500 rpm
✅ Correct Answer: (C)
2570
Q. From the following data of a 60 degree V-twin engine, determine the maximum value for primary forces in newtons:Reciprocating mass per cylinder = 1.5 Kg Stroke length = 10 cm Length of connecting rod = 25 cm Engine speed = 2500 rpm
✅ Correct Answer: (A)
7711
Q. In the given figure, m1=10 Kg, m2=30Kg and m=50 Kg, if r=0.3m, l=1m, find l2 = 0.5m, find r1 in m.
✅ Correct Answer: (B)
0.75
Q. From the given data, find the balancing mass’s inclination in degrees if r=0.2m required in the same plane.Masses = 200kg, 300kg, 240 kg, 260Kg,
✅ Correct Answer: (A)
201.48
Q. Which of the following statements are associated with complete dynamic balancing of rotating systems? 1. Resultant couple due to all inertia forces is zero. 2. Support reactions due to forces are zero but not due to couples . 3. The system is automatically statically balanced. 4. Centre of masses of the system lies on the axis of rotation.
✅ Correct Answer: (D)
1, 3 and 4 only
Q. A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 11.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?
✅ Correct Answer: (B)
836
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