Q. To convert volumetric analysis to gravimetric analysis, the relative volume of each constituent of the flue gases is
✅ Correct Answer: (C)
multiplied by its molecular weight
Engineering Thermodynamics MCQs | Page - 4
Dear candidates you will find MCQ questions of Engineering Thermodynamics here. Learn these questions and prepare yourself for coming examinations and interviews. You can check the right answer of any question by clicking on any option or by clicking view answer button.
Q. a heat engine receives heat at the rate of 1500 kJ/min.& gives an output of 8.2 kW. Its thermal efficiency is equal to
✅ Correct Answer: (C)
32.8%
Q. An inventor claims that a new heat cycle will develop 0.4 kW for a heat addition of 32.5 kJ/mm. The temperature of heat source is 1990 K & that of sink is 850K. Is his claim true?
✅ Correct Answer: (B)
false
Q. Consider the following statements: The definition of
1. temperature is due to zeroth law of thermodynamics
2. entropy is due to first law of thermodynamics
3. internal energy is due to second law of thermodynamics
4. reversibility is due to Kelvin-Planck's ststement of these statements
✅ Correct Answer: (C)
1 alone is correct
Q. A heat engine is supplied with 250 kJ/s of heat at a constant fixed temperature of 227°C. The heat is rejected at 27°C. The cycle is reversible, if the amount of heat rejected is
✅ Correct Answer: (D)
150 kj/s
Q. A Carnot engine receiving heat at 400K has an efficiency of 25%. The C.O.P. of a Carnot refrigerator working between the same temperature limits is
✅ Correct Answer: (C)
3
Q. If a heat enine gives an output of 3 kW when the input is 10,000 J/s, then the thermal efficiency of the engine will be
✅ Correct Answer: (B)
30%
Q. In a cyclic heat engine operating between a source temperature of 600°C & a sink temperature of 20°C, the least rate of heat rejection per kW net output of the engine is
✅ Correct Answer: (B)
0.505 kw
Q. In a reversible cycle, the source temperature is 227°C & the sink temperature is 27°C. The maximum available work for a heat input of 100 kJ will be
✅ Correct Answer: (C)
40 kj
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