πŸ“Š Hydraulics
Q. Determine the head over sill of a 90° V-notch when the discharge passing over it is 100 lit/sec. consider Cd 0.6.
  • (A) 0.346 cm
  • (B) 3.46 cm
  • (C) 0.346 m
  • (D) 3.46 m
πŸ’¬ Discuss
βœ… Correct Answer: (C) 0.346 m
πŸ“Š Hydraulics
Q. A 12 m long weir is subdivided by four intermediate vertical posts each 0.6 m wide. If the weir is discharging under a head of 0.5 m, calculate discharge using Francis formula.
  • (A) 5.895 m3/sec
  • (B) 5.895 m3/hr
  • (C) 5.895 lit/sec
  • (D) 5.895 lit/ hr
πŸ’¬ Discuss
βœ… Correct Answer: (A) 5.895 m3/sec
πŸ“Š Hydraulics
Q. As the flow moves in the pipe, fluid pressure decreases.
  • (A) true
  • (B) false
  • (C) all
  • (D) none
πŸ’¬ Discuss
βœ… Correct Answer: (A) true
πŸ“Š Hydraulics
Q. The velocity of liquid particles at the centre of pipe is less than the velocity of particles near the inner surface of pipe.
  • (A) true
  • (B) false
  • (C) all
  • (D) none
πŸ’¬ Discuss
βœ… Correct Answer: (B) false
πŸ“Š Hydraulics
Q. The frictional resistance is proportional to the velocity in laminar flow
  • (A) true
  • (B) false
  • (C) all
  • (D) none
πŸ’¬ Discuss
βœ… Correct Answer: (A) true
πŸ“Š Hydraulics
Q. The fR depends on the nature of the surface of contact in laminar flow.
  • (A) true
  • (B) false
  • (C) all
  • (D) none
πŸ’¬ Discuss
βœ… Correct Answer: (B) false
πŸ“Š Hydraulics
Q. Head loss due to entry.
  • (A) h = 0.5 V12/2g
  • (B) h = 0.5 V22/2g
  • (C) h = (V2 – V3)2/2g
  • (D) h = 0.5 V32/2g
πŸ’¬ Discuss
βœ… Correct Answer: (A) h = 0.5 V12/2g
πŸ“Š Hydraulics
Q. Head loss due to exist.
  • (A) h = 0.5 V12/2g
  • (B) h = 0.5 V22/2g
  • (C) h = (V2 – V3)2/2g
  • (D) h = 0.5 V32/2g
πŸ’¬ Discuss
βœ… Correct Answer: (D) h = 0.5 V32/2g
πŸ“Š Hydraulics
Q. Head loss due to sudden contraction.
  • (A) h = 0.5 V12/2g
  • (B) h = 0.5 V22/2g
  • (C) h = (V2 – V3)2/2g
  • (D) h = 0.5 V32/2g
πŸ’¬ Discuss
βœ… Correct Answer: (B) h = 0.5 V22/2g
πŸ“Š Hydraulics
Q. Head loss due to sudden enlargement.
  • (A) h = 0.5 V12/2g
  • (B) h = 0.5 V22/2g
  • (C) h = (V2 – V3)2/2g
  • (D) h = 0.5 V32/2g
πŸ’¬ Discuss
βœ… Correct Answer: (C) h = (V2 – V3)2/2g

Jump to