Q. Determine Output
Code:void main()
{
char *p="hi friends", *p1;
p1=p;
while(*p!='\0') ++*p++;
printf("%s", p1);
}
✅ Correct Answer: (B)
ij!gsjfoet
Explanation: ++*p++ will be parse in the given order :
1. *p that is value at the location currently pointed by p will be taken
2. ++*p the retrieved value will be incremented
3. when ; is encountered the location will be incremented that is p++ will be executed.
1. *p that is value at the location currently pointed by p will be taken
2. ++*p the retrieved value will be incremented
3. when ; is encountered the location will be incremented that is p++ will be executed.