Q. What will be the output of this code?
Code:
void main()
{
int i=0;
for(;i++;printf("%d", i));
printf("%d", i);
}
✅ Correct Answer: (A)
1
Explanation: Before entering into the for loop checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).