πŸ“Š Ruby
Q. What is the output of the given code?
for num in 1..3
puts num*num
m= 0
loop do
m += 1
puts m
break if m == 3
end
end
  • (A) 12345678910
  • (B) 1 1 2 3 4 1 2 3 9 1 2 3
  • (C) 1 4 9 16 25
  • (D) None of the mentioned
πŸ’¬ Discuss
βœ… Correct Answer: (C) 1 4 9 16 25

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