Q. What does the & operator do when used with a proc in Ruby?
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(A)
Invokes the proc with the given arguments
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(B)
Converts the proc into a lambda so it can be passed to a method that expects a lambda parameter
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(C)
Converts the proc into a block so it can be passed to a method that expects a block parameter
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(D)
Converts the proc into a method so it can be called directly
✅ Correct Answer: (C)
Converts the proc into a block so it can be passed to a method that expects a block parameter