Q. What is the output of the following program?
Code:
from math import sqrt L1 = [x**2 for x in range(10)].pop() L1 + = 19 print(sqrt(L1), end = " ") L1 = [x**2 for x in reversed(range(10))].pop() L1 + = 16 print(int(sqrt(L1)))
β
Correct Answer: (C)
10 .0 4