Q. What is the output of the following piece of code?
Code:
#mod1 def change(a): b=[x*2 for x in a] print(b) #mod2 def change(a): b=[x*x for x in a] print(b) from mod1 import change from mod2 import change #main s=[1,2,3] change(s)
β
Correct Answer: (D)
There is a name clash