Q. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
✅ Correct Answer: (D)
364
Explanation: L.C.M. of 6, 9, 15 and 18 is 90
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
So Required number = (90 x 4) + 4 = 364
Explanation by: Mr. Dubey
L.C.M. of 6, 9, 15 and 18 is 90
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
So Required number = (90 x 4) + 4 = 364
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
So Required number = (90 x 4) + 4 = 364