R

Ruchi Sharma • 9.87K Points
Tutor III Math

Q. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

  • (A) 74
  • (B) 94
  • (C) 184
  • (D) 364
  • Correct Answer - Option(D)
  • Views: 962
  • Filed under category Math
Explanation by: Mr. Dubey
L.C.M. of 6, 9, 15 and 18 is 90
Let required number be 90k + 4, which is multiple of 7
Least value of k for which (90k + 4) is divisible by 7 is k = 4
So Required number = (90 x 4) + 4 = 364

You must be Logged in to update hint/solution

Discusssion

Login to discuss.

Question analytics