Q. Population of a town increase 2.5% annually but is decreased by 0.5% every year due to migration. What will be the percentage increase in 2 years?
✅ Correct Answer: (B)
4.04%
Explanation: Net percentage increase in Population = (2.5 - 0.5) = 2% each year.
Let the Original Population of the town be 100.
Population of Town after 1 year = (100 + 2% of 100) = 102.
Population of the town after 2nd year = (102 + 2% of 102 ) = 104.04
Now, % increase in population = 4.04/100×100=4.04%
Mind Calculation Method:
100 == 2% Up(1st year) ==> 102 == 2%Up(2nd year) ==> 104.04
% population increase in 2 years = 4.04%.
Let the Original Population of the town be 100.
Population of Town after 1 year = (100 + 2% of 100) = 102.
Population of the town after 2nd year = (102 + 2% of 102 ) = 104.04
Now, % increase in population = 4.04/100×100=4.04%
Mind Calculation Method:
100 == 2% Up(1st year) ==> 102 == 2%Up(2nd year) ==> 104.04
% population increase in 2 years = 4.04%.
Explanation by: Sandeep
Net percentage increase in Population = (2.5 - 0.5) = 2% each year.
Let the Original Population of the town be 100.
Population of Town after 1 year = (100 + 2% of 100) = 102.
Population of the town after 2nd year = (102 + 2% of 102 ) = 104.04
Now, % increase in population = 4.04/100×100=4.04%
Mind Calculation Method:
100 == 2% Up(1st year) ==> 102 == 2%Up(2nd year) ==> 104.04
% population increase in 2 years = 4.04%.
Let the Original Population of the town be 100.
Population of Town after 1 year = (100 + 2% of 100) = 102.
Population of the town after 2nd year = (102 + 2% of 102 ) = 104.04
Now, % increase in population = 4.04/100×100=4.04%
Mind Calculation Method:
100 == 2% Up(1st year) ==> 102 == 2%Up(2nd year) ==> 104.04
% population increase in 2 years = 4.04%.