πŸ“Š Math
Q. 18 years ago, a man was three times as old as his son. Now, the man is twice as old as his son. The sum of the present ages of the man and his son is = ?
  • (A) 54 years
  • (B) 72 years
  • (C) 105 years
  • (D) 108 years
βœ… Correct Answer: (D) 108 years

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