Q. The greatest number, which when subtracted from 5834, gives a number exactly divisible by each of 20, 28, 32, 35 is.
✅ Correct Answer: (B)
4714
Explanation: LCM of 20, 28, 32, 35 will be the greatest number which is divisible by these numbers.
Firstly, we find LCM of 20, 28, 32, 35
20 = 2 × 2 × 5
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
35 = 5 × 7
LCM = 2 × 2 × 2 × 2 × 2 × 5 × 7 = 1120
Required greatest number which subtract from 5834 are divide by 20, 28, 32 and 35
= 5834 - 1120
= 4714
Firstly, we find LCM of 20, 28, 32, 35
20 = 2 × 2 × 5
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
35 = 5 × 7
LCM = 2 × 2 × 2 × 2 × 2 × 5 × 7 = 1120
Required greatest number which subtract from 5834 are divide by 20, 28, 32 and 35
= 5834 - 1120
= 4714
Explanation by: Virat Bhati
LCM of 20, 28, 32, 35 will be the greatest number which is divisible by these numbers.
Firstly, we find LCM of 20, 28, 32, 35
20 = 2 × 2 × 5
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
35 = 5 × 7
LCM = 2 × 2 × 2 × 2 × 2 × 5 × 7 = 1120
Required greatest number which subtract from 5834 are divide by 20, 28, 32 and 35
= 5834 - 1120
= 4714
Firstly, we find LCM of 20, 28, 32, 35
20 = 2 × 2 × 5
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
35 = 5 × 7
LCM = 2 × 2 × 2 × 2 × 2 × 5 × 7 = 1120
Required greatest number which subtract from 5834 are divide by 20, 28, 32 and 35
= 5834 - 1120
= 4714