Q. A can do ¼ of a work in 10 days. B can do ⅓ of the work in 20 days. In how many days can both A and B together do the work ?
✅ Correct Answer: (D)
24 days
Explanation:
A's 1-day work = (1/4) ÷ 10 = 1/40
B's 1-day work = (1/3) ÷ 20 = 1/60
(A + B)'s 1-day work = 1/40 + 1/60
= (3 + 2)/120
= 5/120
= 1/24
Therefore, time taken by both together = 24 days.
Answer: (D) 24 days
Explanation by: Roshan
A's 1-day work = (1/4) ÷ 10 = 1/40
B's 1-day work = (1/3) ÷ 20 = 1/60
(A + B)'s 1-day work = 1/40 + 1/60
= (3 + 2)/120
= 5/120
= 1/24
Therefore, time taken by both together = 24 days.
Answer: (D) 24 days