Q. Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?
✅ Correct Answer: (A)
4
Explanation: N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)
= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4
Explanation by: Mr. Dubey
N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)
= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4
= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4