M

Mr. Dubey • 100.64K Points
Coach Math

Q. Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?

  • (A) 4
  • (B) 5
  • (C) 6
  • (D) 8
  • Correct Answer - Option(A)
  • Views: 539
  • Filed under category Math
Explanation by: Mr. Dubey
N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)
= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4

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