πŸ“Š Math
Q. Radha get married 6 years ago. Today her age is 5/4 times her age at the time of marriage. Her son's age is 1/10 times her age. Her son's age is :
  • (A) 1 years
  • (B) 2 years
  • (C) 3 years
  • (D) 4 years
βœ… Correct Answer: (C) 3 years

Explanation: Let us assume the present age of Radha be Y years; then
Before 6 years Radha's age will be Y - 6 years.
According to question,
Today her age is 11/4 times her age at the time of marriage,
5/4 ( Y - 6 ) = Y ( Since 11/4 = 5/4 )
⇒ 5Y - 30 = 4Y
∴ Y = 30 years
Hence, her son's age = 30 x 1/10 =3 years

Explanation by: Harikesh
Let us assume the present age of Radha be Y years; then
Before 6 years Radha's age will be Y - 6 years.
According to question,
Today her age is 11/4 times her age at the time of marriage,
5/4 ( Y - 6 ) = Y ( Since 11/4 = 5/4 )
⇒ 5Y - 30 = 4Y
∴ Y = 30 years
Hence, her son's age = 30 x 1/10 =3 years

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