Q. The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
✅ Correct Answer: (C)
174 runs
Explanation: Let the highest score be n.
∴ Lowest score = n – 172
According to question ,
∴ n + n – 172 = 40 × 50 – 38 × 48
⇒ 2n – 172 = 2000 – 1824 = 176
⇒ 2n = 176 + 172 = 348
∴ n = 348 ÷ 2 = 174
Explanation by: Vaibhav Shukla
Let the highest score be n.
∴ Lowest score = n – 172
According to question ,
∴ n + n – 172 = 40 × 50 – 38 × 48
⇒ 2n – 172 = 2000 – 1824 = 176
⇒ 2n = 176 + 172 = 348
∴ n = 348 ÷ 2 = 174
∴ Lowest score = n – 172
According to question ,
∴ n + n – 172 = 40 × 50 – 38 × 48
⇒ 2n – 172 = 2000 – 1824 = 176
⇒ 2n = 176 + 172 = 348
∴ n = 348 ÷ 2 = 174