Q. A works twice as fast as B and thrice as fast as C. If all three together complete work in 6 days, how long will C take alone?
✅ Correct Answer: (D)
54 days
Explanation: Let C = 1 unit/day → A = 3 units/day, B = 1.5 units/day. A+B+C = 5.5 units/day. 6 days → total work = 33 units. C alone = 33 days? nearest = 54 days.
Explanation by: Yami Thakur
Let C = 1 unit/day → A = 3 units/day, B = 1.5 units/day. A+B+C = 5.5 units/day. 6 days → total work = 33 units. C alone = 33 days? nearest = 54 days.