Q. A bag contains 6 red and 4 blue balls. Two balls are drawn without replacement. What is the probability that one is red and one is blue?
✅ Correct Answer: (A)
8/15
Explanation: Required probability = (6/10 × 4/9) + (4/10 × 6/9) = 48/90 = 8/15.
Explanation by: Krishna Sharma
Required probability = (6/10 × 4/9) + (4/10 × 6/9) = 48/90 = 8/15.