Q. The sum of all integers between 200 and 400 divisible by 9 is

✅ Correct Answer: (B) 6633

Explanation:

Multiples of 9 between 200 and 400 are:

First multiple = 207 (9 × 23)
Last multiple = 396 (9 × 44)

This is an AP:
a = 207
l = 396
d = 9

Number of terms:
n = (396 - 207)/9 + 1
= 189/9 + 1
= 21 + 1
= 22

Sum of AP:
S = n/2 × (a + l)
= 22/2 × (207 + 396)
= 11 × 603
= 6633

Answer: (B) 6633

Published by Mr. Dubey ⭐ 111.22K Points at 20-Aug-2020 03:35 pm in Math

Multiples of 9 between 200 and 400 are:

First multiple = 207 (9 × 23)
Last multiple = 396 (9 × 44)

This is an AP:
a = 207
l = 396
d = 9

Number of terms:
n = (396 - 207)/9 + 1
= 189/9 + 1
= 21 + 1
= 22

Sum of AP:
S = n/2 × (a + l)
= 22/2 × (207 + 396)
= 11 × 603
= 6633

Answer: (B) 6633

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