Quiz on Math Set 130

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Quiz on Math Set 130 :

Question 1 :

There are just two ways in which 5 may be expressed as the sum of two different positive (non-zero) integers, namely 5 = 4 + 1 = 3 + 2. In how many ways, 9 can be expressed as the sum of two different positive (non-zero) integers?
A. 3
B. 4
C. 5
D. 6

Correct Ans: Option B

Question 2 :

P and Q are two positive integers such that PQ = 64. Which of the following cannot be the value of P + Q?
A. 16
B. 20
C. 35
D. 65

Correct Ans: Option C

Question 3 :

If n is an integer between 20 and 80, then any of the following could be n+7 except
A. 47
B. 58
C. 84
D. 88

Correct Ans: Option D

Question 4 :

If x, y, z be the digits of a number beginning from the left, the number is
A. xyz
B. x + 10y + 100z
C. 10x + y + 100z
D. 100x + 10y + z

Correct Ans: Option D

Question 5 :

How many numbers between  1000 and 5000 are exactly divisible by 225 ?
A. 16
B. 18
C. 19
D. 12

Correct Ans: Option B

Question 6 :

If m and n are positive integers and (m – n) is an even number, then (m2 – n2) will be always divisible by
A. 4
B. 6
C. 8
D. 12

Correct Ans: Option A

Question 7 :

When a number is divided by 56, the remainder obtained is 29. What will be the remainder when the number is divided by 8 ?
A. 4
B. 5
C. 3
D. 7

Correct Ans: Option B

Question 8 :

(49)^15 – 1 is exactly divisible by :
A. 50
B. 51
C. 29
D. 8

Correct Ans: Option D

Question 9 :

If a and b are two odd positive integers, by which of the following integers is (a^4 – b^4) always divisible ?
A. 3
B. 6
C. 8
D. 12

Correct Ans: Option C

Question 10 :

A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be ?
A. 0
B. 4
C. 6
D. 3

Correct Ans: Option C

Quiz Summary


Here the correct answers of every question in this quiz.

Q.1 [B],     Q.2 [C],     Q.3 [D],     Q.4 [D],     Q.5 [B],     Q.6 [A],     Q.7 [B],     Q.8 [D],     Q.9 [C],     Q.10 [C],    


Total Questions: 10
Your score:
Subject: Math
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