Q. What is the result of the recurrences which fall under the extended second case of Master’s theorem (let the recurrence be given by T(n)=aT(n/b)+f(n) and f(n)=nc(log n)k?
✅ Correct Answer: (C)
t(n)= o(nc (log n)k+1
Explanation: in the extended second case of master’s theorem the necessary condition is that c = logba. if this condition is true then t(n)= o(nc(log n))k+1.