Q. The turnover numbers for the enzymes E1 and E2 are 150 s-1 and 15 s-1 respectively. This means

• (A) E1 binds to its substrate with higher affinity than E2
• (B) The velocity of reactions catalyzed by E1 and E2 at their respective saturating substrate concentrations could be equal, if concentration of E2 used is 10 times that of E1
• (C) The velocity of E1 catalyzed reaction is always greater than that of E2
• (D) The velocity of E1 catalyzed reaction at a particular enzyme concentration and saturating substrate concentration is lower than that of E2 catalyzed reaction under the same conditions