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Correct Answer: (A)
19.89 khz
Explanation: resonant frequency of hartley oscillator is given by 1/ 2π√(c1 (l1 + l2)). substituting the given values in the above equation, cut-off frequency is 19.89 khz.
Explanation by: Mr. Dubey
resonant frequency of hartley oscillator is given by 1/ 2π√(c1 (l1 + l2)). substituting the given values in the above equation, cut-off frequency is 19.89 khz.
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