If the moment of inertia of a section about its axis is and its effective sectional area is , its radius of gyration r about the axis, is

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Q. If the moment of inertia of a section about its axis is and its effective sectional area is , its radius of gyration r about the axis, is

(A) r = i/a
(B) r i/a)
(C) r = (i/a)
(D) r a/i)

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✅ Correct Answer: (B) r i/a)

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