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M

Mr. Dubey • 100.64K Points
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Q. If the moment of inertia of a section about its axis is and its effective sectional area is , its radius of gyration r about the axis, is

  • (A) r = i/a
  • (B) r i/a)
  • (C) r = (i/a)
  • (D) r a/i)
  • Correct Answer - Option(B)
  • Views: 31
  • Filed under category Design of Steel Structures
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