What is the percent composition of a mixture of (S)-(+)-2-butanol,[!] D/25 = +13.52º, and (R)-(-)-2-butanol,[!] D/25 = -13.52º, with a specific rotation [!] D/25 = +6.76º? | Faculties

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📊 Pharmaceutical Organic Chemistry 3

Q. What is the percent composition of a mixture of (S)-(+)-2-butanol,[!] D/25 = +13.52º, and (R)-(-)-2-butanol,[!] D/25 = -13.52º, with a specific rotation [!] D/25 = +6.76º?

(A) 75%(R) 25%(S)
(B) 25%(R) 75%(S)
(C) 50%(R) 50%(S)
(D) 67%(R) 33%(S)

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✅ Correct Answer: (B) 25%(R) 75%(S)

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