Q. What is the output for the below code?
public class Test{
public static void main(String[] args){
byte b = 6;
b+=8;
System.out.println(b);
b = b+7;
System.out.println(b);
}
}

  • (A) 14 21
  • (B) 14 13
  • (C) Compilation fails with an error at line 6
  • (D) Compilation fails with an error at line 6 D. Compilation fails with an error at line 4
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βœ… Correct Answer: (C) Compilation fails with an error at line 6
Explanation: int or smaller expressions always resulting in an int. So compiler complain about Type mismatch: cannot convert from int to byte for b = b+7; But b += 7; // No problem because +=, -=, *=, and /= will all put in an implicit cast. b += 7 is same as b = (byte)b+7 so compiler not complain.
Explanation by: Praveen Singh
int or smaller expressions always resulting in an int. So compiler complain about Type mismatch: cannot convert from int to byte for b = b+7; But b += 7; // No problem because +=, -=, *=, and /= will all put in an implicit cast. b += 7 is same as b = (byte)b+7 so compiler not complain.

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