Q. What happens if the following program is compiled and executed?
interface MyInterface{
void display();
}
interface MySubInterface extends MyInterface{
void display();
}
public class Test implements MySubInterface{
public void display(){
System.out.print("Welcome to Examveda.");
}
public static void main(String args[]){
Test t = new Test();
t.display();
}
}
interface MyInterface{
void display();
}
interface MySubInterface extends MyInterface{
void display();
}
public class Test implements MySubInterface{
public void display(){
System.out.print("Welcome to Examveda.");
}
public static void main(String args[]){
Test t = new Test();
t.display();
}
}
✅ Correct Answer: (C)
The code will compile and execute successfully showing the output Welcome to Examveda.
Explanation: The program will compile and execute successfully as you can declare methods with same name in an interface and the method of either interface can be used, implying the option a is incorrect. The option B and D are incorrect as the methods of an interface are implicitly public and abstract.