Q. What will be printed after executing following program code?
class Base{
int value = 0;
Base(){
addValue();
}
void addValue(){
value += 10;
}
int getValue(){
return value;
}
}
class Derived extends Base{
Derived(){
addValue();
}
void addValue(){
value += 20;
}
}
public class Test{
public static void main(String[] args){
Base b = new Derived();
System.out.println(b.getValue());
}
}
class Base{
int value = 0;
Base(){
addValue();
}
void addValue(){
value += 10;
}
int getValue(){
return value;
}
}
class Derived extends Base{
Derived(){
addValue();
}
void addValue(){
value += 20;
}
}
public class Test{
public static void main(String[] args){
Base b = new Derived();
System.out.println(b.getValue());
}
}
✅ Correct Answer: (C)
40
Explanation: When object of new derived is called, the flow goes to Derived() first, by default super(); is present in Derived() as the first statement, so the flow now goes to Base. Here value is initialised to 0 and then addValue() is called. The addValue has been overridden in Derived() hence The Base's addValue() will perform value+20(0+20) .After this control flows back to Derived()'s addValue() where again value+20 is done (20+20). Hence Answer is 40