Q. What is the result of the following code snippet?
try {
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}
try {
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}
✅ Correct Answer: (A)
NullPointerException!
Explanation: In the given code snippet, a NullPointerException is explicitly thrown within the try block. When an exception is thrown, the Java runtime looks for a catch block that matches the type of the thrown exception.